Check my answers? :3 f(t) = 6 + cos(t/10) + 3sin(7t/40) is used to model the velocity of the plane, in miles per minute, for 0 ≤ t ≤ 40 what is the total distance traveled by the plane over the time interval 0 ≤ t ≤ 40? (I got 236.651 miles ???) If at time t=5 the test plane is at mile marker 15 along the straight test track, determine the position of the plane at time t=25. (I got 161.659 miles ???)
JIGGLY! LONG TIME NO SEE
part a is correct http://www.wolframalpha.com/input/?i=%5Cint_0%5E%7B40%7D++6+%2B+cos%28t%2F10%29+%2B+3sin%287t%2F40%29
you can do that cuz the given velocity function is never negative
yeah, even then all you would have to do is put abs value in there somewhere XD :P thanks :)
how about for the other part? :3
the other part requires taking indefinite integral, solving for the constant and finding d(25) uhmm
let me check quick...
6t + 10sin(t/10) - (120/7)cos(7t/40) + C plugged in t=5 found C= 1.194 ? plugged in t=25 -> 161.658 ?
\(\large d(t) = 6t + 10\sin(\frac{t}{10}) - \frac{120}{7}\cos(\frac{7t}{40})+c\)
wolfram says c = -8.8 ? http://www.wolframalpha.com/input/?i=+6*5+%2B+10%5Csin%28%5Cfrac%7B5%7D%7B10%7D%29+-+%5Cfrac%7B120%7D%7B7%7D%5Ccos%28%5Cfrac%7B7*5%7D%7B40%7D%29%2Bc+%3D+15
check once.. .
oh yeah I see what I did wrong, I made it equal 25 instead of 15 :P whoops
ohk :)
so plugged in 25 -> 152.854 ??? :3
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great! :D Thanks!!! :)
np :)
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