Question

How do you solve for x in this equation?
3 = log8 + 3logx

Answer 1

By law of logs nloga => logaⁿ, we have:

3 = log(8) + log(x³)

When adding logs, you are multiplying the terms altogether.

3 = log(8x³)

Then, by log_a b = n ==> aⁿ = b:

10³ = 8x³ [Since the base is not given, I assume that the base is 10]
1000 = 8x³

Finally, solve for x.

1000/8 = x³
x³ = 125
x = (125)^(1/3) . . .Set both sides to the power of 1/3.
x = 5

Hence, x = 5.

Answer 2

Source: http://answers.yahoo.com/question/index?qid=20110221095929AAWSPzY

Answer 3

x=5 does no appear to be the correct answer.
Refer to the attached from WolframAlpha.

Answer 4

Thank youuuu

Answer 5

Hmm... Interesting @robtobey .

Thanks for the heads up!

Answer 6

Sorry, left a t off of the end of no.

Answer 7

Me or tobey? @cayssaday cause Tobey got the right one

Answer 8

Both of you !!:)

Answer 9

Lol no prob! ;)

Answer 10

Both of you put the thought into helping me so thank you :)