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what is the equation of a line that is perpendicular to -x+3y=2
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there can be many lines of the form \[y+3x=c\] where c is any constant
First, let's isolate y (get it by itself) so the line is in slope-intercept form (y=mx+b). -x + 3y = 2 -x + x + 3y = x + 2 3y = x + 2 3y/3 = (x + 2)/3 y = x/3 + 2/3 y = (1/3)x + 2/3 We can pull out our slope, m: 1/3. Remember that parallel has the same slope, and perpendicular has the opposite reciprocal (flip the fraction, change the sign). We can take 1/3 and do just that. First, we'll flip it: 3/1, which simplifies to 3. Now, we change the sign: -3. There's your slope. You can make the y-intercept (b) anything you like, but to keep it simple, it can just be 0: y = -3x
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