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Chemistry 7 Online
OpenStudy (amtran_bus):

*checking my work* Conjugate base

OpenStudy (amtran_bus):

Give the conjugate base for each of the following acids: a) HClO b) NH4+ C)HN3 d)HS- Is it: a) ClO- b) NH3 c) N3- d) S^2-

OpenStudy (amtran_bus):

@abb0t @aaronq

OpenStudy (amtran_bus):

Also, Give the conjugate base for each of the following acids: a) HNO3 b) HCOOH c) C6H5COOH d) CH3NH3+ Is it: a) NO3- b) COOH- C) C6H5COO- d) CH3NH2-?

OpenStudy (accessdenied):

Most look good to me from what I know on this. The only one I see is (d) on the second set. You went from CH3NH3+ to a CH3NH2- , which is 2 charges taken off +1-2=-1 for one hydrogen omitted

OpenStudy (amtran_bus):

Thank you. So it should be CH3NH2+?

OpenStudy (amtran_bus):

I ment CH3NH2^-1

OpenStudy (accessdenied):

I mean, it started positive 1. CH3NH3+. You correctly omitted the H for CH3NH2, but you are supposed to go from +1 to 0 charge (+1, one proton removed, to +1-1 =0) . CH3NH2

OpenStudy (amtran_bus):

Oh ok I got you. Thanks so much.

OpenStudy (amtran_bus):

Can you check one more for me?

OpenStudy (amtran_bus):

I will open a new ? so I can give you another medal.

OpenStudy (accessdenied):

Sure. Sorry, just one more I should point out. I think HCOO- would be the correct way to write that base rather than COOH-. The former is written more like other acids as the latter would be something slightly different (carboxylic group).

OpenStudy (amtran_bus):

Ok. Will correct that. Thanks so much.

OpenStudy (abb0t):

huh?

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