Question

Really need help with this.
Suppose that a population parameter is 0.1, and many samples are taken from the population. if the size of each sample is 90. which of the following will most likely be the standard deviation of the sample proportions?
A. 0.095
B. 0.032
C. 0.072
D. 0.055

Answer 1

what's the srd dev of a sample proportion?

Answer 2

std, not srd

Answer 3

\[\sigma=\sqrt{p1-p}/n\]

Answer 4

plug in what you know and compute.

btw it's \(\sigma =\sqrt{p\cdot q/n}\) /n inside the sqrt

Answer 5

what would you expect p to be near?

Answer 6

could you plug the numbers into that equation for me please?

Answer 7

why can't you?

Answer 8

what number would go in for q?

Answer 9

q = (1-p)

Answer 10

so it would be \[\sigma=\sqrt{\frac{ .1*.0 }{ 90 }}\]

Answer 11

the .0 is suppose to be .9

Answer 12

yep

Answer 13

so the answer would be B, but really 0.031622777 summed up. Thanks man!

Answer 14

you did all the work!