Question

suppose that, based on a sample, the 68% confidence interval for the mean of a population is (26, 32). what is the value of s/sqrtn?
A. 5
B. 3
C. 2
D. 4

Answer 1

\[\frac{ s }{ \sqrt{n} }\]

Answer 2

68% is 1 standard deviation away from mean

Answer 3

so, \(s\) = (32-26)/2 = 3

Answer 4

so its B?

Answer 5

the question is asking u to find \(\large \frac{s}{\sqrt{n}}\),

Answer 6

you got \(\large s = 3\)

Answer 7

im not sure how to find \(n\)

Answer 8

well 3 over something is closer than i was before so thank you

Answer 9

on second thoughts,

\(\large \frac{s}{\sqrt{n}} = 3\) is right

Answer 10

correct option is B

Answer 11

\(3\) is the margin of error for given confidence interval, its not standard deviation

Answer 12

and, margin of error for 68% data is simply \(\large \frac{s}{\sqrt{n}}\)

Answer 13

ahaha thank you, it was 3, i passed the test

Answer 14

yayyy! wonderful xD congrats !!