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expand the logarithmic expression log(4x^3)/y^2(x-1)^5
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\[\log(4x ^{3}/y^2(x-1)^5 ) \]
First you can use log (a/b)=log a -log b
so log4x^3 - log y^2(x-1)^5
Yep
Now open log(4x^3) in terms of sum of logs
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im not sure is it 3log4x-2logy(x-1)^5
Nope log 4x^3=log 4+log x^3=2log 2+3log x Similarly do for 2nd term
ok so 2logy+5log(x-1) ?
Right :)
so I put them over each other or subtract the two........... 2log2+3logx-2logy+5log(x-1) ?
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It should be -5log(x-1) and you are done
how did it come out to that
@AravindG
I just subtracted the 2 terms
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