Question

2B203+4C=1B4C3+2CO2
If 100.0 grams C reacts with 85.0 g B203, How many grams of B4C3 Will be produced?

Answer 1

I believe you have to find the limiting reactant first. Convert the given masses to their respect # of moles by dividing by their respective molar masses. The reactant that has the lowest # of moles will be your limiting reactant. Use stoichiometry to find the amount of moles B4C3 can be made from the limiting reactant. Finally, multiply the amount of moles of B4C3 by its molar mass to get the mass. DEEP BREATH. Good luck.

Answer 2

Thanks haha Never came to solving it but thanks