Question

combine into single log...

Answer 1

\[\log_{5}2+\log_{5}(x+1)-1/3\log_{5}(3x+7) \]

Answer 2

Just a heads up, this offers the log "rules" , you could say.
http://www.rapidtables.com/math/algebra/logarithm/Logarithm_Rules.htm
Check it out, unless your problem is a bit more complex, i'll gladly assist to the best of my ability.

Answer 3

You can just use the addition log rule and then use the subtraction log rule to combine that, so just check out the website.
Give it an attempt!

Answer 4

so do I do each part seperately

Answer 5

Yeah.

Answer 6

As i said above, use the addition rule to combine them, then use the subtraction rule.

Answer 7

is the first part 5log2?

Answer 8

5log2+5log(x+1)-5*1/3log(3x+7) ?

Answer 9

The first part is:
\[\ \log_5 2 + \log_5 (x+1) = \log_5 2(x+1) \]
Then:
\[\ \log_5 2(x+1) - \frac {1}{3} \log_5 (3x+7) \]
Finally:
\[\ \frac{\log_5 2(x+1)}{\frac{1}{3} (3x+7)} \]
Simplfies to:
\[\ \frac{\log_5 6(x+1)}{(3x+7)} \]

Answer 10

Sorry it should be:
\[\log_5 \left( \frac{ 6(x+1) }{3x+7 } \right)\]

Answer 11

I messed up when manually writing the LaTeX.
xD

Answer 12

ok thnks I get it

Answer 13

do u mind if I write u 2 problems I did them just wana kno if they r right @shamil98