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Physics 8 Online
OpenStudy (anonymous):

If someone could help explain a concept to me that would be great! There's a parallel L-C circuit with an alternating voltage source (picture will be attached) and one part of the question asks what the current drawn from the voltage source is when the circuit is at its resonant frequency (omega = 1/sqrt(LC) ). I know that the answer is 0 but it would be great to hear the reasoning behind it! Cheers

OpenStudy (anonymous):

OpenStudy (anonymous):

Never mind, I found it! For anyone else's future reference: "At the resonant frequency of the circut, the voltage source can supply voltage easily because the parallel L-C circuit draws no current at all! (For this reason, a parallel L-C circuit can be used as a filter to pass signals at the resonance frequency.) Of course, the same current flows in the inductor and the capacitor as the current that flows when they are driven separately by the voltage source. However, the currents are exactly out of phase, so that the net effect is a current circulating around the loop made by the capacitor and the inductor without passing into or out of the voltage source."

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