In a soluble solution, is water always a reactant?
I am currently studying the acid-base chapter in my textbook, and I don't understand how to set up the equation so that it is applicable to finding the pH. How do I set this up? And what steps do I take to solve for all of the concentrations needed to find the pH? 1)What is the pH of a 0.50 M(molarity) solution of sodium nitrite at 25.0 (degrees) Celsius? The Ka is given for HNO2 at 25 (degrees) Celsius: 4.5 x 10^-4.
Wheres Wolfe when you need him? -.-
TToTT
@e.mccormick You know this one?
I have a quiz tomorrow~ please recruit help!!!
It''s been too long since I have done these
I tried every other site I could think of...and it's pretty traumatic because Google has failed me...and that's pretty bad...ToT *cry face*
If this question is going to be on the quiz then it has to be something that was taught to you or atleast in your textbook. Try checking through your notes or go through your textbook.
All I remember is \(\large pH = -\log_{10}[H^+]\) or I guess it's \([H_3O^+]\)
I flipped through the notes and the textbook as well, but it bever tells me what to put on what side of the equation.... I mean, there is like, HA-->H+A but I went through some of the equations and they're different sometimes...
oh yes this is more complicated because it's a weak acid, oh dear even more that I don't remember too well.
TToTT It's more complicated because it's a weak acid??? How~?
hang on a sec, lemme work on it .-.
well you need to use the pKa, it's not just a simple complete dissociation as in a strong acid. but urgh I was googling stuff but omg I am too distant from chemistry to remember all this @_@
Thank you~~~ *tears of gratefulness*
Wait hold on. If it's a strong acid/base, that means that with water, it would dissociate? And then if it's anything weak(HA/HB) then I have to use pKa?
just tagging our chemistry expert :) @chmvijay
The powerful summoning of the ChemMaster~ ^^
or...maybe no?
Reposting this question so it's answered ^^: If it's a strong acid/base, that means that with water, it would dissociate? And then if it's anything weak(HA/HB) then I have to use pKa?
So, you mainly need in the numerical, right?
yeah...? Uhm, like setting up the equation and then finding the concentrations of the species that are not given... and also, since in this one specifically, it gives the NaNO2 concetration of .5 Molarity, instead of giving me the HNO2 or something like that...
NaNo2 + H2O ----> HNO2 + NaOH First off that will be the equation , and we need to find pH of NaNo2 or HNO2?:S
Ohhh hold on, since we can say that Na=an observer ion(?Right?) then the OH is left alone, find the pOH, and subtract from 14?
Hmm yea !
hmm... seems that way... but then what was @kirbykirby saying about the dissociation thing?
and is the H2O always going to be on the reactants side?
Yeah Its sodium nitrate solution , so YES!
"solution"
wait yes to the first or second?
question
I mean the H20 will always be on the reactant side
ohhhh YESHHHHHH oh my gosh the world just lit up a little~ and back to what @kirbykirby said...If it's a strong acid/base, it would dissociate? And then if it's anything weak(HA/HB) then I have to use pKa?
Yes if we r using strong acid/base then only it will dissociate otherwise we have to use pKa!
H2o is strong enough to cause dissociation , so we dont need to use pKa
Wow Cyber...I never knew you had all dis knowledge o_O
hmmm...so how to tell what to use...like, for this equation, I wouldn't even be able to use Ka=([H] {A])/(HA)...............
hehe shad :P
And there's 4 types of Titration curve problems, so...
see our equation is NO2- + H2O <--> HNO2 + OH-
Kb = [HNO2][OH-]/[NO2-]
Ka= (products)/(reactants) and it involves H
But Ka is already given to us in the question isnt it? Why do u need to find it
oh, if I wanted to find the molarities of any of the species in the formula...but I suppose I don't really need that....
Would you mind too awfully if I asked another question? Kind of related~
Lol No , Shoot ~
thanks~ uhm, so: The question is: 0.5 mole of nitrous acid and 0.1 mole of potassium nitrite are added to enough water to make 1.0 liter of solution at 25(degrees Celsius)... and the first part is to get the pH, and the second part is: Calculate the pH after 0.010 mole of HCl is added
do not consider water in the equation :)
oh ok...hmmm...
but I would use it when calculating molarity?
yup :)
and I wouldn't add any of the other's volume because they are virtually insignificant...right?
oh hoold on never mind the total is 1 haha
so first thing is that potassium is an observer ion?
wait would HNO2 and KNO2 go on the same side??? the reactants side>??? OoO nooooo...
Yeah!
They wont be on same side
And Pottasium is an observer ion
sooo.... NO2+ H2O <--->HNO2 + OH?
Yea!
And so what happens to the equation when HCl is thrown in?
HCl + KNO2 ---> KCl + HNO2
Is there a water anywhere in there?
Nope
Water all around my island
hmmm... oh snap...the Ka is for HNO2, but...it's still products/reactants...hmm... does it matter where exactly the HNO2 is in the equation???
hmm no, HNO2 will always be in the product side .-.
right...but then this one equation keeps tripping me up... Ka=[(H)(A)]/(HA)
Ok What exactly is tripping u up? :P what in this equation?
http://scramlinged.com/resources/Notes+on+Weak+Acids+and+Bases.pdf the equation at the top, just in case my weird typing was hard to look at ^^ uhm, it's the fact that making the HA and the H2O not on the same side...the fact that there is a OH instead of an H~ or an H3O
Because then... if I wanted to, could I use this equation?: HNO2+H2O-----> NO2+H3O
hmm actually yea , u cant use this equation .-.
OoO why? uhoh.
cos HA and H20 cant be on the same side, Anion reacts with H20 to make HA .-. jeez
And... how can I find the pH of that second equation HCl+KNO2---> KCl+HNO2 if there's no water...???
wait if Cl and K are deemed observer ions, that would make sense...but then...how did you decide to use KNO2? was it becasue it's a product of the first equation?
KNO2 is in the solution? then we add Hcl into it? did that make sense? Thats how we used it
ohhhhhhh oh my gosh hahaha and so you know of a way to eassily memorize the main strong acids? That's something major that I haven't found out how to memorize quite right yet... :|
basically hydrides of halogens and p block elements are strong acids..........the bigger the period of the atom attached to Hydride , the stronger the acid
HI (halogen attached), >HNO3(oxygen and nitrogen , P-block)
did that make sense? :P
sort of? Whats a hydride?
compounds of hydrogen (with a H in it) for e.g (H)Cl , NH3
ohhhh haha and so H with anything in the p block would make a good strong acid?
Yeah ! and as the period number increases more acidic it will be! some acids even have 2 p-block elements attached to em for eg HNO3
But If we have lower P-block period elemets like C then acid will be kinda weak for e.e HCN
C??? but isnt that the same period and only one proton short of N???
Oh wait no i meant Period lol
Yeah its one proton short thats why its weak :P
and btw therer is an excpetion H2s is kinda weak , it is because it hydrogen bonds and doesnt give out H+ ions
u will learn all this stuff in inorganic chemistry or chemical bonding chapters
So...generally, it has to also be something that could stand on it's own just fine? like HF, and the H can detacha dnt the F has to become F2?
for the record HF is weak acid too cos it has strong Bond Between H and F due to small sizes and its tough to remove H+ ion
i d sugest to give a reading to P=Block elements chapter or Chemical Bonding Chapter
that will explain all of these concepts
HCL and HI are strong acids cos they can easily release H+ ion and they will make Cl2 ,and I2 respectively
hmmm so...things that are bigger in period, yet the more easily they are able to lose protons, the better. And then they are most...or alll? in the p-block
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