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exterior angle of a regular polygon is 10o how many sides with there be?
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One thing to be noted: the sum of all exterior angles in *any* polygon is 360 degrees.
The number of exterior angles, obviously, is the same as the number of sides.
So we've got the two things above for us. Now... let's say that the number of sides is \(n\). Then the number of exterior angles would be \(n\). It's given that one exterior angle is equal to \(10^{\circ}\). And we know that the sum of exterior angles is \(360^{\circ}\). So we're left with the following equation:\[10 \times n = 360\]
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