Question

A gas station stores its gasoline in a tank under the ground. The tank is a cylinder lying horizontally on its side. (In other words, the tank is not standing vertically on one of its flat ends.) If the radius of the cylinder is 2.5 meters, its length is 7 meters, and its top is 2 meters under the ground, find the total amount of work needed to pump the gasoline out of the tank. (The density of gasoline is 673 kilograms per cubic meter; use g=9.8 m/s^2.)

Answer 1

Just drawing a picture here:

Answer 2

here,

d(density)= 673Kg/m^3
g=9.8m/sec

put volume of cylinder = pi X r^2 X h
where r is radius and h is height

we know,

work = force X displacement
= mass X acceleration X displacement
= density X volume X acceleration X displacement

@VozMajal can you do the rest of the calculation.

Answer 3

Please ignore the bottom line of my drawing.

Answer 4

here displacement is the height of the cylinder as it is placed horizontally.

Answer 5

If it's just D(V)(a)(d), then I can do it, the only thing is, to find Volume, you need to know "h". Would that be the 2 meters?

Answer 6

Well h=7 isn't it

Answer 7

That would make sense. We can pretend that I didn't ask that, right?

Answer 8

Of course :)

Answer 9

So, after plug and chugging, I ended up with 1,814,855.272, which I'm guessing is far from correct.

Answer 10

unit?

Answer 11

Joules?

Answer 12

I haven't calculated it myself yet, but why do you think that it's far from correct?

Answer 13

Because the grader said so. Hahah

Answer 14

I think it should be Joules as all the units are in SI system rather than the CGS so, I think the unit should be joules.

Answer 15

That's what I thought as well.

Answer 16

Well I ended up with 1813005.26641 but I don't know if it is correct

Answer 17

I just got that as well, and it isn't. :\