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Mathematics 14 Online
OpenStudy (mallorysipp234):

HOW DO I FIND THE AVERAGE COMMON RATIO OF A GEOMETRIC SERIES.

OpenStudy (amistre64):

if its a geometric sequence we have the setup: \[g,~gr,~gr^2,~gr^3,...\] \[\frac{gr^k}{gr^{k-1}}=r\]

OpenStudy (amistre64):

in other words, just take some term, and divide it by the term before it ... 1,3,9,18, 3/1 = 3 9/3 = 3 18/9 = 3 etc ....

OpenStudy (mallorysipp234):

OpenStudy (amistre64):

hmmm, that seems a bit more complicated :)

OpenStudy (mallorysipp234):

yeah. :/ @amistre64

OpenStudy (amistre64):

a ratio a:b can be considered a fraction a/b an average is a sum divided by how many there are .... one idea may be that you can add up 5 ratio amounts and divide by 5 ... naybe

OpenStudy (amistre64):

or, if we are trying to get a geometric sequence that starts at 3 and ends at 1.2 in 5 terms ...

OpenStudy (mallorysipp234):

yes, i have 5 terms, the first number is 3, and the last number is 1.2. i need to know what the average common ratio of that is.. i dont understand how to get it.

OpenStudy (amistre64):

\[g_n = g_{n-1}~r\] \[g_n = g_{0}~r^{n-1}\] \[1.2 = 3~r^{4}\] divide and 4rt

OpenStudy (amistre64):

or work some logs

OpenStudy (mathmale):

@chell: Please post your own question separately. Type it into the "Ask a question" box.

OpenStudy (mallorysipp234):

@amistre64 okay. so 1.2 = 3 r^4 and solve that? and that's my common ratio?

OpenStudy (amistre64):

if we are wanting to form a geometric sequence that starts at 3, and the 5th term is 1.2 .... then yes

OpenStudy (mallorysipp234):

okay so that's 0.795 that's my common ratio?

OpenStudy (amistre64):

sounds good to me .... assumptions in tow

OpenStudy (amistre64):

to keep accuracy, 4rt(.4) might be warranted as an exact result

OpenStudy (mallorysipp234):

@amistre64 can you help me with this part???

OpenStudy (mallorysipp234):

What is the height of each ball on the fifth bounce (i.e., Height 6)? Use the geometric sequence formula, an = a1rn – 1 and show your work. a1 = r^n-1

OpenStudy (amistre64):

well, we know r, and the height for 5 ... so multiply r by H5 to get H6

OpenStudy (amistre64):

what is 1.2, times 4rt(.4)?

OpenStudy (mallorysipp234):

1.272

OpenStudy (amistre64):

1.2 * .795 is not more than 1.2 ....

OpenStudy (amistre64):

79% of 1.2 is not greater than 100% of 1.2 :)

OpenStudy (mallorysipp234):

oh its .954 what does that have to do with this though?

OpenStudy (amistre64):

well, 3*r^4 = 1.2 for height 5. what is height 6? tack on another r :/ ... 3*r^5

OpenStudy (mallorysipp234):

yes. @amistre64 that makes sense.

OpenStudy (amistre64):

wow, i just got a notice that someone needs to learn something by today ... procrastination is such a blessing :)

OpenStudy (mallorysipp234):

@amistre64 thank you for your help. i really appreciate it. (:

OpenStudy (amistre64):

good luck ;)

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