compute d2y/dx2 at the point (-2, 3). x^3+y^3= 19

Question

terenzreignz · Answer

You'd do well to first differentiate the equation (twice) with respect to x, of course.

ipwnbunnies · Answer

That means you treat 'y' as a constant. :)

terenzreignz · Answer

No it doesn't... it means you treat y as a function of x ^_^

anonymous · Answer

Just give me the answer

terenzreignz · Answer

But it will give you an entirely different (read: wrong) answer.

terenzreignz · Answer

It's implicit differentiation.

terenzreignz · Answer

Also, giving answers isn't allowed @Pedro_Belman 
Sorry ^_^
I risk suspension if I do that.

ipwnbunnies · Answer

Just go with what terenz is saying. I might be thinking ahead of myself with multivariable calculus.

terenzreignz · Answer

That's the spirit @iPwnBunnies :3
Now, @Pedro_Belman 
You have to differentiate the entire expression, with respect to x, treating y as a function of x.
So by chain rule, and what-not, after differentiating both sides, you get
$$\large 3x^2 + 3y^2 \frac{dy}{dx}= 0$$
Now differentiate again ^_^

anonymous · Answer

Oh ok thanks :D

terenzreignz · Answer

That's not the answer yet, you know :3
Not quite there yet... although if you can carry on from here, I'll be happy enough :>