Question

What is the oxidation number for each atom in NH4Cl?

A.



N=+3, H=-4,Cl=+1


B.



N=+3, H=+1,Cl=-1


C.



N=-3, H=-1,Cl=+1


D.



N=-3, H=+1,Cl=-1

Answer 1

@TwoPointInfinity

Answer 2

@quinnisaghost

Answer 3

@LadyKatsaTheGraceling

Answer 4

@madeline.grey

Answer 5

@Monica75

Answer 6

idk sorry

Answer 7

KK

Answer 8

break it into it's respective polyatomic ions \(NH_4^+\) and \(Cl^-\).

so clearly, Cl is =-1

H is almost always +1 (except when it's a hydride), in this case H=+1

that leaves us with: \(\underbrace{+4}_{H} + \underbrace{(-1)}_{Cl}+ \underbrace{x}_{N} = 0\) ; where x is the oxidation state of N.