The figure shown is a regular pentagon. What is the value of p? a regular pentagon with one exterior angle labeled three p. twenty-four degrees fifty-two degrees seventy-two degrees one hundred eight degrees
@mathstudent55
If you have a regular pentagon, that means you have 5 sides.
Also, all sides are congruent, and all angles are congruent.
I still don't know :'(
Using the formula of the sum of the measures of the interior angles, can you find the sum of the measures of the interior angles? 180(n - 2) Using 5 for n.
so 540! :)
but thats not an option _-_
You need to learn patience. A problem like this does not consist of one single step. We need a few steps to find the answer. Great. All interior angles add up to 540 degrees. Correct. Since there are 5 of them how much does each one measure? 540/5 = ?
I know, sorry. 540/5=108 so now that is the answer, thank you!
No it isn't.
but why not?
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We found that each interior angle measures 108 degrees. The question is what is p, isn't it?
yes, yet again you are right, I am wrong, sorry.
Now we see that the interior angle of 108 degrees and the exterior angle measuring 3p are supplementary angles. That means their measures add up to 180 degrees.
so now the question is asking 3 times p + 108 = 180 correct?
Now we write an equation to express that and we solve it for p. 108 + 3p = 180 Subtract 108 from both sides. Then divide both sides by 3. Then you'll have p.
Correct. You got the right equation. Now solve for p.
so 24, correct?
Correct.
Here's another way of doing it. The sum of the measures of the exterior angles of a polygon, taken one per vertex, is 360. You know you have a pentagon, so you have 5 vertices. Since the pentagon is regular, all sides are congruent, all interior angles are congruent, and all exterior angles are congruent. Since you have 5 exterior angles (one per vertex), divide 360 by 5 to find that each exterior angle measures 72 degrees. The problem is showing that 3p = 72. Solve 3p = 72 for p and get p = 24.
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