Evaluate arctan(-squareroot(3)/3) for an exact radian value in terms of pi.
what do you know about arctan(-x) ?
What i wrote was all that was given. From what i've understood so far it's in Q1.
Yes, the reason I asked what arctan(-x) equals to is because you need to use the identity to evaluate the given expression
It equals the angle of theta, no?
so arctan(-x) = x?
yes
or... wouldnt arctan(-x) equal tan(x)?
no, arctan(-x) = -arctan(x). This is the identity that will help you evaluate. So using the identity, what does the expression now equal to?
-arctan(squareroot(3)/3)...?
good. so if you let Θ = arctan(sqrt(3) / 3), what does this equivalent to?
and that's where you lose me.
well, it's equivalent to tan(Θ) = sqrt(3)/3
gotcha
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so 30 degrees since it's a 30 60 90 triangle, then convert to radians?
so what angle whose tangent is sqrt(3)/3 ?
which would be pi over 6?
excellent. But remember that you also have a negative sign in the front
so 330 degrees convert to radians, or negative pi over 6?
yep
so are negative pi over 6 and 11pi over 6 both valid answers? and thank you, you're a lifesaver
no, just pi/6.
i mean just -pi/6
gotcha. thank you again.
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