The equation e^(4x) + x=2 has a solution near x=0. By replacing the left side of the equation by its linearization, find an approximate value for the solution. **Write the EXACT answer** x=_______ please explain!!! Thank you:)
|dw:1395094405168:dw| in case it wasn't clear when typed:)
the linearization method find f'(x) if f(x)=e^(4x)+x then the linear equation that f(x) is approximately y=mx+b where m=f'(0) in case since we want to know what happens near x=0 the y-intercept can be found by using a point on the line which we know to be (0,f(0))=(0,1) correct?
yes:)
so we need to find f'(x) first?
yep
so would f'(x)= e^(4x) + 0 = e^(4x)?
f'(x)=(4x)'e^(4x)+(x)'
(4x)'=4 (x)'=1
ohh darn... using the chain rule?
Yippie
so f'(x)= 5 ?
So we have f'(0) is totally 5 good job so we have y=5x+b we need the y-intercept now
we know this line goes through (0,e^(4*0)+0)
Use that to find b
so 0=5(0)+b b=0?
e^0=?
a^0=1 whenever a does not equal 0
oh oops e^0=1 so 1= 0+b b=1?
yep so we have the approximation for f(x) is y=5x+1 So now you solve 5x+1=2 and you are done.
5x+1=2 -1 -1 -------- 5x=1 x=1/5 so exact answer is x= 0.2 ?
what that is an approximation since we approximated f(x) to be y.
oops well not what*
that is the exact approximation they are looking for
ohh okay.. does that mean to 0.2 is the answer to this problem then? :o
yep if i have read the question correctly and by exact answer they mean the exact answer they are looking for and not the exact solution to e^(4x)+x=2
ohh okay i see:) awesome! thank you1! :D
Np. Are you doing online homework?
yes:/ my teacher assigned both online and written :( but i guess i get more practice! :)
fun stuff
haha i know right? all this homework makes me jump with joy :P
^^i wish :P
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