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Chemistry 16 Online
OpenStudy (anonymous):

Need help explaining.. To write out a balance chemical reaction for a combustion, will it always include O2 in the reactant? For example, coal. Would I write it out as C + O2 -> CO2?? And how would I know how many moles of each to write out?

OpenStudy (aaronq):

yeah. you can't burn anything without oxygen. moles? like in terms of the coefficients?

OpenStudy (anonymous):

yes. the coefficients. thank you for responding! :)

OpenStudy (aaronq):

you always wanna use the lowest numbers possible so if the reaction is balanced you don't need to include more numbers.

OpenStudy (anonymous):

ohh i see. so let's say i write the reaction for ethanol... would i start like this? C2H5OH + O2 ?

OpenStudy (aaronq):

yes, your products would be CO2 and H2O (assuming complete combustion, in real life you get some CO as well).

OpenStudy (anonymous):

how do you know what the product will look like? i'm horrible at stoichiometry, i think that's what it's called

OpenStudy (aaronq):

we'll for combustion reactions it's always the same thing \(CO_2+H_2O\). For other types of reactions it's different, of course. Have you gone through the 5 categories? (single-, double displacement, etc.)

OpenStudy (anonymous):

i don't believe i have. categories of what?

OpenStudy (aaronq):

of types of reactions. I'm sure you have by now.

OpenStudy (anonymous):

do you learn all of that in general chemistry also?

OpenStudy (aaronq):

yeah, it's one of the first things you learn after drawing lewis and bohr diagrams. They're single displacement, double displacement, decomposition, synthesis and acid-base, does that ring a bell?

OpenStudy (anonymous):

acid-base and maybe decomposition does sound familiar, not the others though. unless the book did go through it but i just didn't understand it.

OpenStudy (aaronq):

hm thats possible, they're usually presented all together. If you need a refresher you should look it up on youtube there are tons of great videos. Ask here after if you need clarification on any of them.

OpenStudy (anonymous):

awesome. Thank you! :)

OpenStudy (aaronq):

no problem, good luck !

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