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Mathematics 10 Online
OpenStudy (anonymous):

Can someone help me on my Precalculus homework I'll attach a picture above...

OpenStudy (anonymous):

Here's the pic of my homework, I don't know how to find the inverse of a function, also I don't know how to find the values of problems number 3-8, please help!!

OpenStudy (mathmale):

It'd be less confusing for everyone if you'd post just one problem at a time. On which one would you like to focus right now?

OpenStudy (anonymous):

On number 3 please!

OpenStudy (mathmale):

First and foremost: the function y=arccos x is the inverse of the function y = cos x. If you see "y=arccos x," think, "y is the angle that has cosine equal to x." For example, arccos (1/2) is the angle that has cosine equal to 1/2, and that angle is 60 degrees. Check this on your calculator: cos 60 deg = 1/2.

OpenStudy (mathmale):

Note: arccos (-1) could be re-written as arccos (-1/1). Since the cosine function is defined as cos theta = adjacent side / hypotenuse, the adjacent side here is -1 and the hypotenuse is 1. Could you draw that? Use the Draw feature, below, if possible.

OpenStudy (anonymous):

how do you know that 1/2 is equal to 60 degrees?

OpenStudy (mathmale):

You probably have either a calculator or a table of trig function values. If I were to ask you, "what is the sine of 30 degrees?" to where would you go for that information?

OpenStudy (anonymous):

the unit circle?

OpenStudy (mathmale):

There's something called a 30-60-90 (degree) triangle: From this triangle you can get the values of all six of the trig functions: sine, cosine, tangent, cotangent, secant and cosecant:|dw:1395101187278:dw|

OpenStudy (mathmale):

the unit circle should work fine also. But you still have to know the definitions of all 6 trig functions.

OpenStudy (anonymous):

Hmm. So, if I were to use the unit circle for this the answer for number 3 would be 180°? Am I right?

OpenStudy (mathmale):

Yes. I'd like to see how you got that: arccos (-1) = arccos (-1/1) => adj side is -1 and hypotenuse is 1, so we have an arrow of length 1 pointing from the center of our circle leftward tothe point (-1,0). Yes, the angle is 180 deg. Nice work! Note that 180 deg = pi radians.

OpenStudy (anonymous):

I guided myself by seeing this unit circle. I found that 180° equals (-1,0) that it is equal to (cos, sin) so, the answer would be 180°... Am I ok? :D

OpenStudy (mathmale):

It's great if you can successfully use the unit circle. "I found that 180° equals (-1,0) that it is equal to (cos, sin) " unfortunately is inaccurate. You could state that the adjacent side is the line segment from the origin (0,0) to the point (-1,0): It's -1. The radius of this circle is 1, so the hypotenuse is 1. What are you trying to say with, "that it is equal to (cos,sin)"?

OpenStudy (anonymous):

That the cos of 180° is -1 and the sine of it is 0 :o

OpenStudy (mathmale):

You're quite right there. Please be careful not to write things such as "that it is equal to (cos,sin)" that lead to others' having to guess your meaning. So: What's your final answer to this question? Is it possible that there could be more than one correct answer?

OpenStudy (anonymous):

The answer is 180° but, since my teacher is asking me this on radians it would be pi!

OpenStudy (mathmale):

that's right!

OpenStudy (anonymous):

Thank you very much! :D Could you please help me on number 4?!

OpenStudy (mathmale):

Please post #4 as a separate question, OK?

OpenStudy (anonymous):

Ok! :D

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