Which of the following shows a pair of equations that are equivalent?
D
D.
No. it's not D
is D correct @robtobey
One of those sets of equations....if you multiply out the first equation, you get the 2nd equation.
D is correct
No....On D if you multiply out the first equation. 8 + 4(x + y) = 12 you get 8 + 4x + 4y = 12 that's not 12 (x + y) = 12
D is not correct.
You can't add the 8 to the 4 before distributing.
Expand A for me, please...
\[8+4(x+y) = 12\] what is that after you remove the parentheses by distributing the 4?
8+4=12
\[4(x+y) = 4\]?!?
\[4(x+y) = 4*x + 4*y\]
let's make it a bit more real. We'll say that x = 2 and y = 3. \[4(x+y) = 4(2+3) = 4*5 = 20\]If we use the distributive property, as I did:\[4(x+y) = 4*x + 4*y = 4*2 + 4*3 = 8 + 12 = 20\] Let's try it with a different pair of numbers: x = 3, y = 5 \[4(x+y) = 4(3+5) = 4*8 = 32\]\[4(x+y) = 4*x + 4*y = 4*3 + 4*5 = 12+20 =32\] Are you convinced that this works yet?
so it would be B?
@whpalmer4
You still haven't expanded either equation in A for me yet. Why are you guessing at answers, when you could determine the answer correctly?
\[8 + 4(x+y) = 12\]Expand that using the distributive property, as I just demonstrated on \(4(x+y)\)
4x – 8 = 4(x – 2)
How on earth did you come up with that?
\[8 + 4(x+y) = 12\]Do not touch the 8. Do not touch the 12. Just change \(4(x+y)\) to its equivalent using the distributive property. All you have to do is multiply 4 by each of the two things inside the ( )!
ITS D
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