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Mathematics 14 Online
OpenStudy (vshiroky):

help

OpenStudy (vshiroky):

@hoblos

OpenStudy (vshiroky):

I think it's 5

OpenStudy (johnweldon1993):

To make something have a POSITIVE exponent...You simply put it Under 1 So \[\huge \frac{1}{125^{\frac{2}{3}}}\] Now \(\huge 125^{2/3}\) can be written as \(\huge \sqrt[3]{125^2} \) So \[\huge \frac{1}{\sqrt[3]{125^2}} = \space ?\]

OpenStudy (vshiroky):

so 11.2?

OpenStudy (johnweldon1993):

Not quite...\(\huge \sqrt[3]{125^2} = 25\) so we have \(\huge \frac{1}{25} \)

OpenStudy (vshiroky):

1/25 is the answer?

OpenStudy (johnweldon1993):

Correct :)

OpenStudy (vshiroky):

Thanks!

OpenStudy (johnweldon1993):

No problem :)

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