Find the derivative of f(x) = 6/x at x = -2. help
Rewrite f(x) so x is in the numerator. It'll be easier to take the derivative.
how do i do that
\[\Large\bf\sf f(x)\quad=\quad \frac{6}{x}\]Use this rule of exponents, as bunny mentioned. \[\Large\bf\sf \frac{1}{x}\quad=\quad x^{-1}\]
so x^-6
Nooo you silly billy!\[\Large\bf\sf \frac{6}{x}\quad=\quad 6\frac{1}{x}\quad=\quad 6x^{-1}\]
Do you understand how I was able to pull the 6 out of the numerator like that?
i think so
but i don't get what to do after that
Power ruuuuule \c:/
Remember your power rule?
POWUH RULE IS THE BESTTT RULE.
One Power to Rule Them All!! \c:/
my guess is you are supposed to do this by hand, not power rule
do you put it under a radical
my guess is you have to compute \[\lim_{x\to -2}\frac{f(x)-f(-2)}{x-(-2)}\]
does that look familiar?
How you not learned the shortcut rules at this point? Still using the limit definition of derivative? A little clarity would help ^^
would the answer be 3/2?
the derivative of \(\frac{1}{x}\) is \(-\frac{1}{x^2}\) so the derivative of \(\frac{6}{x}\) is \(-\frac{6}{x^2}\)
so i was right?
if \(x=-2\) you get \(-\frac{6}{(-2)^2}\) or \(-\frac{3}{2}\)
you were off by a minus sign
ohh.. darn. well thank you for helping :)
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