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Show that if $a$, $b$ and $c$ are positive integers with $(a,b) = 1$ and $ab = c^n$, then there positive integers $d$ and $e$ such that $a = d^n$ and $b = e^n$.
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write each number in factored form since the gcd is 1, all the prime factors are different
Could you show me what you mean
\[a=p_1^{\alpha_1}p_2^{\alpha_2}...p_k^{\alpha_k}\]\[b=q_1^{\beta_1}q_2^{\beta_2}...q_k^{\beta_j}\] where \(p_i\neq q_l\)
then write \(ab=c^n\) and note that since all the prime factors are different , you can write it as \(d^n\times e^n\)
i guess you should point out that if the product is \(c^n\) then all the exponents in each prime factorization is divisible by \(n\) so maybe the way i wrote it was not so good
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