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Physics 9 Online
OpenStudy (anonymous):

pls help...

OpenStudy (anonymous):

hold on :)

OpenStudy (anonymous):

http://screencast.com/t/rhOCTGTXM8q

OpenStudy (anonymous):

the correct answer is D

OpenStudy (anonymous):

@inkyvoyd @satellite73

OpenStudy (anonymous):

how do i do it?

OpenStudy (anonymous):

thanks

OpenStudy (theeric):

Hi! I can help :) You know that electrical potential is greatest at the positive terminal, and goes to \(0\) at the negative terminal as a reference, right? You also know that the voltage (energy per charge) will drop as electrons lose energy due to resistance, right? Or, at the least, you know resistors cause a "voltage" drop. Lastly, the connections are assumed to have no resistance, and so no voltage drop. Those are the principles that will help you mark the voltage from X to Y. Is that helpful?

OpenStudy (theeric):

Ohhhhhh! One more thing. A greater resistance implies a greater "voltage drop."

OpenStudy (theeric):

(More resistance means more energy lost through the resistor.)

OpenStudy (theeric):

The steeper drop is the more dramatic voltage loss. So, you look at the order of those, too.

OpenStudy (anonymous):

and how exactly can i come to the correct answer

OpenStudy (theeric):

So, start at X. You have have the starting voltage at that point because there's no resistance at that point, right?

OpenStudy (theeric):

@thushananth01 ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

v at x will be maximum, so less voltage drop through resistor X and the gradient would be less steeper, and then no voltage drop trough the connections and then more voltage drop through resistor Y which would produce a more steeper gradient.. therefore D the answer it is>

OpenStudy (theeric):

Yep!

OpenStudy (anonymous):

thanks alot..mind helping me with another question?

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