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Trigonometry
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OpenStudy (anonymous):
Suppose that the functions u and w
u(x)=x^2+5
w(x)=sqrtx+7
Find the following.
(u o w)(2)
(w o u)(2)
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OpenStudy (anonymous):
what is \(w(2)\) ?
OpenStudy (anonymous):
@ganeshie8 can you help with this?
ganeshie8 (ganeshie8):
\(\large (u~o~w)(2)\)
is same as
\(\large u( ~w(2)~)\)
ganeshie8 (ganeshie8):
start by finding \(w(2)\)
ganeshie8 (ganeshie8):
\(\large w(x)=\sqrt{x+7}\)
\(\large w(2) = ?\)
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OpenStudy (anonymous):
are you saying to substitute x for 2 then evaluate?
ganeshie8 (ganeshie8):
yup !
OpenStudy (anonymous):
\[w(x)=\sqrt{2+7}\]
ganeshie8 (ganeshie8):
simplify
OpenStudy (anonymous):
\[=\sqrt{9}=3\]
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ganeshie8 (ganeshie8):
yes !
ganeshie8 (ganeshie8):
\(\large (u~o~w)(2) = u(~w(2)~)\)
\(\large ~~~~~~~~~ ~~~~~~~= u(~3~)\)
\(\large ~~~~~~~~~~~~~~~~~ = ?\)
OpenStudy (anonymous):
so now I am substituting 3 for x?
ganeshie8 (ganeshie8):
yes,
u do that in u(x) ok ?
OpenStudy (anonymous):
14?
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ganeshie8 (ganeshie8):
\(\large (u~o~w)(2) = u(~w(2)~)\)
\(\large ~~~~~~~~~ = u(~3~)\)
\(\large ~~~~~~~~~ = 3^2+5 = 14\)
ganeshie8 (ganeshie8):
14 is right !
ganeshie8 (ganeshie8):
see if u can find the second one : (w o u)(2)
OpenStudy (anonymous):
4?
ganeshie8 (ganeshie8):
You got it !
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ganeshie8 (ganeshie8):
good job :)
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