Question

sqrt3sinx +cosx=sqrt3

Answer 1

Hint: sin x = 1 and cos x = 0

Answer 2

for asin(x) + bcos(x) = c, the left side can be converted to
k cos(x - θ) with
k = sqrt(a^2+b^2) and to get θ use
tanθ = a/b, then solve for θ

so that the equation would be
kcos(x-θ) = c
then find the solutions for x

Answer 3

Divide both side by V3 (sqr.3)
sin x + cos x/V3 = 1. Replace in the equation 1/V3 = tan Pi/6 =
= (sin Pi/6)/(cos Pi/6).
sin x*cos Pi/6 + sin Pi/6*cos x = 1 = sin Pi/2
Transform the left side by using the trig identity: sin (a + b) = sin a*cos b + sin b*cos a
sin (x + Pi/6) = sin Pi/2
x + Pi/6 = Pi/2 -> x = Pi/2 - Pi/6 = 2Pi/6 = Pi/3