I'll give a medal to who ever tell me a and b
I know the first part K=3.125 How do I get part "b"?
The graph of \(y = |x|\) is equivalent to \(y = x\) over the range \(0 \le x \le \infty\) and symmetrical about \(x=0\), so we can just do half the region and multiply by 2. Integrate the height between \(y_2 = 0.08x^2+k\) and \(y_1 = x\): \[2\int_0^{6.25}(0.08x^2+k-x)\,dx\]to get your answer.
So K determines "b"? (meaning the 6.25)
This is what I got \[2\int\limits_{0}^{6.25}(0.08x^2+3.125-x) dx = 13.0208\]
Yes, because k shifts the parabola up or down, which clearly has a big impact on the surface area.... In fact, if you leave \(k\) as a variable and do the integral, you end up with \-26.0417+12.5k\]so the answer is very sensitive to the value of \(k\) Yes, I got the same result. I hope it is correct, it's late :-)
as you can see by my failed formatting...
although I guess the limits of integration will also be altered by changing \(k\)
Webassign didn't take it :( I didn't think it was going to take it either way because it is asking to round to five decimal places
Thanks but I already used all my tries
I don't see see why you entered 13.0208 if it said round to 5 decimal places...an exact answer is 625/48, which is 13.0208333...
Oh man, I didn't get the rest of the answer on my calculator. Oh well I still got an A, thx though.
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