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Physics 20 Online
OpenStudy (anonymous):

Please help

OpenStudy (anonymous):

http://screencast.com/t/lSctJkFTK @theEric

OpenStudy (theeric):

Hi! So one important thing that will make this easier is that you can assume that the voltmeter has a really, really high resistance so that it's hardly involved in the circuit. It will be like an open switch: nothing there.

OpenStudy (anonymous):

okay?

OpenStudy (anonymous):

which means current doesnt flow through it

OpenStudy (theeric):

Pretty much! :)

OpenStudy (anonymous):

voltage is zero

OpenStudy (theeric):

So, you want to look at the difference in electrical potential between the points. That's what the voltmeter will measure.

OpenStudy (anonymous):

how do u calculate that

OpenStudy (theeric):

Voltage is not going to be zero, there. Or maybe, but not necessarily...

OpenStudy (anonymous):

yeah i got it.. u find the voltage two points up and below and find the difference, the answer is 0.5V

OpenStudy (theeric):

Okay! So, you compare the voltage drops! You start from positive like you did when you traced from X to Y. So you start with 3V for each branch. Each branch must have a voltage drop of 3V. The top branch drops it across two equivalent resistors. ... Lemme check! I didn't calculate.

OpenStudy (anonymous):

no i found for the resistor one above at the top, and for the resistors right below the top 1, i found the voltage at both points and found the difference

OpenStudy (anonymous):

thanks alot :) my answer is correct..would u help me with another question

OpenStudy (theeric):

Was .5 correct?

OpenStudy (theeric):

I agree. Anyway, post the new question and @ me! If it's not too long, I'll help!

OpenStudy (anonymous):

yes it was

OpenStudy (anonymous):

i did post, please check :)

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