Question

Calculate the Ka or Kb with the given information

a) 0.10M NaCH3CO2
b) pH = 7.27
c) [H+] = 5.4*10^-8

Answer 1

some of it will do this: but not all of it.

so use \(Ka=\dfrac{[HCH_3CO_2][OH^-]}{[NaCH_3CO_2]}\)


Some useful relationships: Ka*Kb=Kw; \([OH^-]*[H^+]=1.0*10^{-14}\)