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Mathematics 8 Online
OpenStudy (anonymous):

Given two sets of numbers, P = {2, 4, 5, 9, 13, 21} and F = {2, 4, 5, 7, 11, 13, 17}, which one of the following sets is equal to P (big u) F? A. {2, 3, 5, 13} B. {2, 2, 4, 4, 5, 5, 7, 8, 11, 13, 13, 17, 21} C. {2, 21} D. {2, 4, 5, 7, 9, 11, 13, 17, 21} E. {1, 2, 3, 5, 8, 12, 19, 26, 38}

OpenStudy (amistre64):

define what the big U tells us about the setup

OpenStudy (anonymous):

\[p \cup f\]

OpenStudy (anonymous):

Thats what it looks like

OpenStudy (anonymous):

@amistre64

OpenStudy (amistre64):

thats what it looks like yes. what does the U tell us? it refers to some specific action that we can do.

OpenStudy (anonymous):

Nevermind i got the answer. It was d Can you help with a different question? @amistre64

OpenStudy (amistre64):

possibly

OpenStudy (anonymous):

You draw two cards from a well-shuffled deck of 52 cards. After you draw the first card, you do not replace it in the deck. The probability of drawing the ace of diamonds on your first draw is 1/52. What is the probability of P(get king of clubs on second draw | get ace of diamonds on first draw)? A. 1/51 B. 1/26 C. 2/51 D. 1/52

OpenStudy (anonymous):

@amistre64

OpenStudy (amistre64):

first, which one would you guess

OpenStudy (anonymous):

Maybe 1/51 @amistre64

OpenStudy (amistre64):

thats what im thinking to. if youve already drawn a card, and its not a king club, then there are 51 possibilities left, and 1 out of them is correct. 1/51

OpenStudy (anonymous):

Thank you

OpenStudy (amistre64):

now, there is a math way to do it: \[P(B|A)=\frac{P(B\cap A)}{P(A)}\]

OpenStudy (amistre64):

\[\frac{\cancel{1/52}~*~1/51}{\cancel{1/52}}\]

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