What is the reduction half-reaction for the following unbalanced redox equation?

Cr2O2 2- + NH3 + → Cr2O3 + N2

A.

Cr2O3 →Cr2O72-

B.

NH4+ → N2

C.

N2 → NH4+

D.

Cr2O72- →Cr2O3

Question

What is the reduction half-reaction for the following unbalanced redox equation?

Cr2O2 2- + NH3 + → Cr2O3 + N2
	
A. 	
	
	 

Cr2O3 →Cr2O72-
 
	
B. 	
	
	 

NH4+ → N2
 
	
C. 	
	
	 

N2 → NH4+
 
	
D. 	
	
	 

Cr2O72- →Cr2O3

praxer · Answer

it is D.

here , in Cr_2O_7^2- Cr in +6 Oxidation state.

in Cr_2O_3  Cr is in +3 oxidation state. 

Since there is decrease in the oxidation state, Hence this the reduction half reaction from the system of chemical equations.

praxer · Answer

@SGTC!  Did you follow this ?  :)

anonymous · Answer

yes thanks