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What is the reduction half-reaction for the following unbalanced redox equation? Cr2O2 2- + NH3 + → Cr2O3 + N2 A. Cr2O3 →Cr2O72- B. NH4+ → N2 C. N2 → NH4+ D. Cr2O72- →Cr2O3
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it is D. here , in Cr_2O_7^2- Cr in +6 Oxidation state. in Cr_2O_3 Cr is in +3 oxidation state. Since there is decrease in the oxidation state, Hence this the reduction half reaction from the system of chemical equations.
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