HELP PLEASE The first four terms of a number sequence is given by: 3,5,7,9 Write down a. The 5th term b. The 10th term c.the nth term,in terms of n. (I got the first two (a,b) but i'm unable to get c)
A sequence \[a_{1}, a _{2}, a_{_{3}} .. . .. .a _{n} \] is an arithmetic sequence if there is a real number d such that for every positive integer k, \[a _{k+1}=a _{k} + d \]
common difference d=5-3=2 tn=a+(n-1)d here a=3 find tn
Didnt understand
Tn is 2n+1
The number \[d = a _{k+1} - a _{k}\] is called the common difference of the sequence.
tn=3+(n-1)2 =3+2n-2 =2n+1
I just said that @surjithayer
Ik and the common difference is 2 here. @rock_mit182
of course and the first term is 3
so you could use this formula
Yeah so how am i going to find the nth term in the terms of n??
i did and found out for the first two
\[a _{n} = a _{1} + (n-1)d\]
where \[a _{n}\] represents the nth term, that you want to find
and n, also represents that nth term
Okay i get it thanks:)
;)
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