how to solve..
How many mg of Mg(OH)2 will be needed to neutralize 25.0 mL of stomach acid if stomach acid is 0.110 M HCl?

2HCl + Mg(OH)2 -- MgCl2 + 2H2O

Question

how to solve..
How many mg of Mg(OH)2 will be needed to neutralize 25.0 mL of stomach acid if stomach acid is 0.110 M HCl?
 

2HCl + Mg(OH)2 --> MgCl2 + 2H2O

aaronq · Answer

approach this like you would any stoichiometry problem, convert the acid to moles and find how many moles of magnesium hydroxide you need.

ipwnbunnies · Answer

This is also helpful:
Molarity (M) = $$\frac{ numbers of moles }{ Volume (L) }$$

anonymous · Answer

thanks

anonymous · Answer

Hai Sweet @camila2014 , WeLcoMe to OpeN stuDy.. !!

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