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OpenStudy (1645323):
Find the zero of this equation :x^2 - 3 = -2x
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OpenStudy (1645323):
the y= form is x^2+2x-3 and you set it equal to zero but i dont know what to do after
OpenStudy (1645323):
so X^2+2x=3 and i get lost
OpenStudy (anonymous):
\[x^2 + 2x -3 = 0\]
now factor them first
then solve for x
OpenStudy (1645323):
so is the stuff i posted wrong?
OpenStudy (anonymous):
the first one you post was legit for this problem
but you are not done yet
you need to factor it
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OpenStudy (1645323):
so (x+1)(X+1)?
OpenStudy (anonymous):
no,
find two number when multiplied, it gives you -3 and when added, it gives you 2
OpenStudy (1645323):
i dont know
OpenStudy (1645323):
3,-1
OpenStudy (anonymous):
yes,
now put that in factored form
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OpenStudy (1645323):
(x+3)(X-1)
OpenStudy (1645323):
is that the answer
OpenStudy (anonymous):
not yet
the question is find all the zeros
so you need to equal each one of the to 0
and solve for x \[(x+3) = 0 \] and \[(x-1) = 0\]
OpenStudy (1645323):
so thats the answer? or is it -3,1?
OpenStudy (anonymous):
correct
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OpenStudy (1645323):
which one?
OpenStudy (1645323):
@helpme1.2
OpenStudy (anonymous):
-3,1 are the zeros
OpenStudy (1645323):
ok
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