Question

Please help! So lost and confused!! :(

Answer 1

i am sorry but i can't open it so i am sorry

Answer 2

3rd option is correct.

Answer 3

solution of \[ax^{2}+bx+c\] is given by

\[x = \frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]

Answer 4

in your equation a=2, b=6, c=-5

Answer 5

\[\huge -5+ 2x^2=-6x\]
\[\huge \rightarrow 2x^2+6x-5=0\]
comparing it with \[\huge \rightarrow ax^2+bx+c=0\] we have
a= 2, b= 6, c= -5
\[\huge x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} =\frac{-6 \pm \sqrt{6^2-4(2)(-5)}}{2*2} \]
\[=\frac{-6 \pm \sqrt{36-4(2)(-5)}}{4} \]