Question

help please

Simplify: cube root of 7 over fifth root of 7

7 to the power of 1 over 5

7 to the power of 8 over 15

7 to the power of 5 over 3

7 to the power of 2 over 15

Answer 1

Are you sure thats the answers?

Answer 2

yea

Answer 3

Yup I see the answer

Answer 4

is it D?

Answer 5

If this is what you mean\[\sqrt{7}/\sqrt[5]{7}\] then it is equal to \[7 ^{\frac{ 1 }{ 2 }}/7^{\frac{ 1 }{ 5 }} \] which is also equal with \[7^{\frac{ 1 }{ 2 }-\frac{ 1 }{ 5 }}\] and so \[7^{\frac{ 3 }{ 10 }}\] that is what i think..

Answer 6

oh...what do you think it is blacklabel?

Answer 7

@BlackLabel

Answer 8

ow wait.. its cube root..
it is then \[7^{\frac{ 1 }{ 3 }-\frac{ 1 }{ 5 }} \] which equals \[7 ^{\frac{ 2 }{ 15}}\]

Answer 9

Yup :)

Answer 10

so D is correct?

Answer 11

Yep

Answer 12

thanks! :D

Answer 13

You re welcome !