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Use a sum-to-product formula to rewrite cos5w+cos2w as a product.
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\[\cos c+\cos d=2\cos \frac{ c+d }{ 2 }\cos \frac{ c-d }{ 2 }\]
\[so: 2\cos \frac{ 5w+2w }{ 2 }\cos \frac{ 5w-2w }{ 2 }, then simplify?\]
@jdoe0001 @surijthayer
\[\frac{ \cos(5w)+\cos(2w) }{ 2 }\]
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is that right?
\(\bf cos(5w)+cos(2w)=2cos\left(\frac{5w+2w}{2}\right)cos\left(\frac{5w-2w}{2}\right) \\ \quad \\ 2cos\left(\frac{7w}{2}\right)cos\left(\frac{3w}{2}\right)\) the denominator "2" is inside the cosine function, is not under the cosine function
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