Question

Fan+Medal!!

Which equation would best help solve the following problem?

The height of a triangle is 6 m more than its base. The area of the triangle is 56 m^2. Find the length of the base.

Answer 1

the area of a triangle = half base * height

Answer 2

A.) http://static.k12.com/bank_packages/files/media/mathml_ec533d8a7c13b01c12f469cc28ee4e7c4994a7e4_1.gif

B.)
http://static.k12.com/bank_packages/files/media/mathml_718bc00f89b908d81095f7147ffff15d3080fc9f_1.gif

C.)
http://static.k12.com/bank_packages/files/media/mathml_561f225085cf5695ebbce7e79bc7a36fb06fa7a8_1.gif

D.)
http://static.k12.com/bank_packages/files/media/mathml_2b9d049e26e90f44842c607248c8588a5d68f080_1.gif

Answer 3

h=b+6
area=56^2
area=1/2*b*h

Answer 4

area = 56 square meteres
if you let length base = x then the height = x + 6

Answer 5

area =56=\[\frac{ 1 }{ 2 }*base *(base+6)\]

Answer 6

as height =base+6

Answer 7

\[56*2=base*(base+6)\]

Answer 8

is it A?

Answer 9

112=base^2+6*base
base^2+6*base-112=0

Answer 10

now solve this quadratic equation

Answer 11

okay I sorta have part two if anyone can help me with that??

Answer 12

yeah ...Q??

Answer 13

post the new one

Answer 14

The height of a triangle is 6 m more than its base. The area of the triangle is 56 m2. Find the length of the base.

A.
7 m

B.
8 m

C.
14 m

D.
15 m

Answer 15

same way it is
56=(1/2)*base*(base+6)
base^2+6*base=112

Answer 16

base^2+6*base-112=0
base^2+14*base-8*base-112=0
base*(base+14)-8*(base+14)=0
(base-8 )*( base+14)=0
base = 8 or base = -14
length can not be negative
so base= 8 m

Answer 17

awesome okay that makes sense!