What is the product of -4 - 7i and its conjugate?
the conjugate of a+bi is a-bi
so the conjugate of -4-7i is -4-(-7i) or -4+7i
so, -33? ((Thank you so very much! Sorry, I missed something so simple!))
The product of a complex number and its conjugate is done so frequently that it is worth learning a little trick: \[(a+bi)(a-bI) = a^2 + abi - abi b^2i^2 \]\[\qquad= a^2 - b^2i^2\]However, \(i=\sqrt{=-1} \implies i^2=-1\) so if we substitute \(-1\) for \(i^2\) we get \[(a+bi)(a-bi) = a^2-b^2i^2 = a^2-b^2(-1) = a^2+b^2\]
You have \(a = -4\) and \(b = -7\) What is \(a^2+b^2=\)
I completely fumble-fingered that first equation: \[(a+bi)(a-bi) = a^2 + abi - abi -b^2i^2\]\[\qquad=a^2-b^2i^2\]
@michaelaford13 do you have a new, improved answer?
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