@hoblos
Rita is writing statements as shown to prove that if segment ST is parallel to segment RQ, then x = 24. Statement Reason 1. Segment ST is parallel to segment QR Given 2. Angle QRT is congruent to angle STP Corresponding angles formed by parallel lines and their transversal are congruent. 3. Angle SPT is congruent to angle QPR Reflexive property of angles. 4. Triangle SPT is congruent to triangle QPR Angle-Angle Similarity Postulate 5. ? Corresponding sides of similar triangles are in proportion. Which equation can she use as statement 5? (2x + 28):28 = 60:35 (2x + 28):28 = 60:95 (2x + 28):60 = 28:95 (2x + 28):95 = 28:35
an advice. People will mostly click on the next question if post too many questions at the same time
@sourwing this is only one question :)
|dw:1395180647953:dw| according to "Corresponding sides of similar triangles are in proportion" DB:AB = EC:AC
or to fit here we must use (AD+DB):AD = (AE+EC):AC
umm this also is not useful ! :S
I guess we can use AB:AC = AD:AC
AB:AC = AD:AE sorry
but what about the (? + ?):_
AB = AD+DB (2x+28)
im confused
yeah I mixed things up :S sorry we have to use PQ:PR = PS:PT where PQ = PS+PQ PR = PT+TR
so it will be (2x + 28):95 = 28:35
ohhh gotcha! thanks :)
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