Rewrite the logarithmic as a ratio of a: (a) a common logarithm (b) a natural logarithm Log X 5
\(\Large log_5x=a\quad ?\)
yea
use the change of base rule, recall -> \(\bf \textit{change of base rule}= log_{\color{red}{ a}}{\color{blue}{ b}}\implies \cfrac{log_{\color{green}{ c}}{\color{blue}{ b}}}{log_{\color{green}{ c}}{\color{red}{ a}}} \\ \quad \\ and\ {\color{green}{ c}}\textit{ could be any value, so long is the same above and below}\)
so c could be 10?
it could be, "anything" really \(\bf \textit{change of base rule}= log_{\color{red}{ a}}{\color{blue}{ b}}\implies \cfrac{log_{\color{green}{ c}}{\color{blue}{ b}}}{log_{\color{green}{ c}}{\color{red}{ a}}} \\ \quad \\ \cfrac{log_{\color{green}{ cheese}}{\color{blue}{ b}}}{log_{\color{green}{ cheese}}{\color{red}{ a}}}\qquad \cfrac{log_{\color{green}{ meow}}{\color{blue}{ b}}}{log_{\color{green}{ meow}}{\color{red}{ a}}}\) 10, e, 27, 1,000,000, anything
ok, what about the common or natural log?
sure, recall that \(\bf ln =log_{\color{green}{ e}}\)
\(\bf \textit{change of base rule}= log_{\color{red}{ a}}{\color{blue}{ b}}\implies \cfrac{log_{\color{green}{ c}}{\color{blue}{ b}}}{log_{\color{green}{ c}}{\color{red}{ a}}} \\ \quad \\ \cfrac{log_{\color{green}{ 10}}{\color{blue}{ b}}}{log_{\color{green}{ 10}}{\color{red}{ a}}}\qquad \cfrac{log_{\color{green}{ e}}{\color{blue}{ b}}}{log_{\color{green}{ e}}{\color{red}{ a}}}\)
oh ok
so just use the change of base rule :)
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