Question

Graph the inequality...

Answer 1

\[y<(x-3)^2\]

Answer 2

@jigglypuff314

Answer 3

first, graph y=(x-3)^2

Answer 4

it should be a parabola? agree?

Answer 5

yes is the vertex (0,0)?

Answer 6

I'm sorry (0,3)?

Answer 7

no,
y=(x-h)^2+k
h is x
k is y
h is 3
and k is 0
so (0,3) is the vertex
y=(x-3)^2+0

Answer 8

so, the y, must touch the 0 y-axis

Answer 9

Based off the equation, does it shift to the left 3 units or shift to the right 3 units?

Answer 10

upward

Answer 11

the graph can't go upward nor downward , since the y or the k vertex is just 0

Answer 12

does the graph shift
<---that way
or this way --->

Answer 13

here you have y=(x-3)^2

Answer 14

i don't know :/

Answer 15

isn't that closer to the form \[y-k=a(x-h)^2\]

Answer 16

the paraola formula is y=(x-h)^2+k
your equation is y=(x-(3))^2
that means 3 is positive, if -3 was in that equation the equation will look like this
y=(x-(-3))^2 -----> y=(x+3)^2
so your equation y=(x-3)^2
has h of 3
and the overall vertex is (3,0)

Answer 17

yeah @hello1213
that's the vertex form of a parabola

Answer 18

also written like this
y=(x-h)^2+k

Answer 19

okay so the vertx is (3,0) or (0,3)?