Problem: Yi and Sue play a game. They start with the number 42000. Yi divides by a prime number, then passes the quotient to Sue. Then Sue divides this quotient by a prime number and passes the result back to Yi, and they continue taking turns in this way. For example, Yi could start by dividing 42000 by 3. In this case, he would pass Sue the number 14000. Then Sue could divide by 7 and pass Yi the number 2000, and so on.
The players are not allowed to produce a quotient that isn't an integer. Eventually, someone is forced to produce a quotient of 1, and that player loses. For example, if a player receives the number 3, then the only prime number (s)he can possibly divide by is 3, and this forces that player to lose. Who must win this game, and why? Explain your reasoning in complete sentences. (Don't just show one example of how the game could go. Instead, explain why the same player must always win, no matter what strategy either player tries to use!) Problem Hints: Try playing sample games with different strategies (but always starting with 42000, with Yi making the first move). Try to figure out why the same player always wins the sample games.
Help? I need not only to have an answer, but explain it clearly with full sentences and correct grammar.
What..?
Sorry, there were just a lot of people who'd view it and then leave when I asked what they thought.
So..what do you think?
I think it's a tough problem.
It is, that's why I need help, LOL.
:P
I want to know, how do you win the game?
My family s never home; I haven't gotten a chance to play it.
...
...
Oh, I see.. nevermind
Sorry
So you start with the number 42000. And Yi gets to go first.
So,...Any ideas? Look at the problem hint. It's supposed to be the key to the solution
Prime Numbers = 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59 and so on..
Yes..I knew that much.
Oh, I get what they're doing.
It says: "Yi divides by a prime number, then passes the quotient to Sue. Then Sue divides this quotient by a prime number and passes the result back to Yi, and they continue taking turns in this way." This is called factoring.
OK...I think I'm following.
So, I think you will have to first find the factors of 42000
Here are all the factors of 42000: (21000,2) (14000,3) (10500,4) (8400,5) (7000,6) (6000,7) (5250,8) (4200,10) (3500,12) (3000,14) (2800,15) (2625,16) (2100,20) (2000,21) (1750,24) (1680,25) (1500,28) (1400,30) (1200,35) (1050,40) (1000,42) (875,48) (840,50) (750,56) (700,60) (600,70) (560,75) (525,80) (500,84) (420,100) (400,105) (375,112) (350,120) (336,125) (300,140) (280,150) (250,168) (240,175) (210,200)
Remember they can ONLY divide 42000 by prime numbers, so we can get rid of the factors that aren't prime numbers.
OK....So, we first get rid of all the ones that are even, right?
@greenlegodude57 ?
(21000,2) (14000,3) (8400,5) (6000,7) These are the ONLY factors of 42000 that are PRIME.
OK.
Then you will have to find the factors of those factors..
The factors of 21000 that are prime are: (10500,2) (7000,3) (4200,5) (3000,7)
I get it now, you can only choose between 4 numbers when you divide this number.
OK.
Let's try an experiment: Let's say Yi divides 42000 by 7: 42000 Sue is left with: 6000 Sue divides by 2: Yi is left with: 3000 Yi divides by 3: Sue is left with: 1000 Sue divides by 2: Yi is left with 500 Yi divides by 5: Sue is left with 50 Sue divides by 5: Yi is left with 5: Yi divides by 5 Sue is left with 1 and Yi wins.
No, if Sue divides 500 by 5 Sue is left with 100.
Oh right, my bad.
Let's say Yi divides 42000 by 7: 42000 Sue is left with: 6000 Sue divides by 2: Yi is left with: 3000 Yi divides by 3: Sue is left with: 1000 Sue divides by 2: Yi is left with 500 Yi divides by 5: Sue is left with 100 Sue divides by 2: Yi is left with 50: Yi divides by 5 Sue is left with: 5 Sue divides by 5 Yi is left with 1 and Sue wins.
It's fine.
OK....
Ah, I messed up again.
Let's say Yi divides 42000 by 7: 42000 Sue is left with: 6000 Sue divides by 2: Yi is left with: 3000 Yi divides by 3: Sue is left with: 1000 Sue divides by 2: Yi is left with 500 Yi divides by 5: Sue is left with 100 Sue divides by 2: Yi is left with 50: Yi divides by 5 Sue is left with: 10 Sue divides by 5 Yi is left with 2 Yi divides by 2 Sue is left with 1 and Yi wins.
OK.
So for most of the time they can only divide by 2 and 5. Because the result of the division will always have even numbers. And you can only sometimes divide even numbers with odd numbers, which is why we rarely used 7 and 3, only in the beginning.
The player is only left with 2 choices after a while, and they all lead the same way. Usually(when you're sue) if you pick 2 instead of 5 you're just making the game longer, because Yi will always win no matter what.
I hope that helps you, I have to go now.
@austinL should be able to help you.
OK...
prime factorization of 42000 : \(42000 = 2^4 3^{1}5^37^1\)
that means, there are \(9\) prime factors in \(42000\)
so, the \(9th\) time who ever picks the result loses cuz, he gets to divide by the "last 9th prime factor" and gets a quotient of "1"
OK.
in the game, can u figure out who picks the result "\(9\) th " time ?
Yi or Sue ?
Well, since Yi goes first, Sue goes second, then Yi does third, then Sue goes fourth, then Yi goes fifth, then Sue goes sixth, then Yi goes seventh, which means Sue goes eight. SO Yi will lose.
? Is that right?
Correct ! so can we conclude this : whoever starts the game first will loose ?
So whoever goes first will lose, that's the solution? It's so simple and brilliant!
Thank you so so so much! You are a life saver.
^^ you got it ! u wlc :)
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