Question

if y=10^(x^2-1), what is y' ?

Answer 1

Have you learned the shortcut rule for differentiating something of the form,\[\Large\bf\sf a^x\]Or no?

Answer 2

http://www.mathsisfun.com/calculus/derivatives-rules.html
enjoy.

Answer 3

ohh..i see a^x(ln a). guess i'll plug those in.

Answer 4

Yah that'll get you on the right track :)
Then don't forget to apply the chain rule after that!!

Answer 5

i got the answer. thanks.

Answer 6

(2x) (ln10) 10^(x^2-1)

Answer 7

yay good job \c:/

Answer 8

\[\ln y=\left( x^2-1 \right)\ln 10\]
\[\frac{ y' }{y }=2x \ln 10,y'=y*2x \ln 10=10^{x^2-1}2x \ln 10\]

Answer 9

Thank you all. :)

Answer 10

yw