Need help understanding number 2.
I don't understand the formula, what does each variable represent?
\(a_1\) is the first number \(r\) is the common ratio (what you multiply one by to get the other) and \(n\) is the number of terms
The terms I'm left with after I figure out the common ratio?
lets to it by example for the first ball
2.4/3
\[a_1=3\\ r=\frac{2.4}{3}=.8\]
New divided by the old.
\[a_5=3\times .8^4\]
right
Wait I was never tolled to times the first number by the number of ratios.
\[a_1,a_2,a_3,a_4,a_5,a_6\\ a_1,a_1r,a_1r^2,a_1r^3,a_1r^4,a_1r^5\]
O_O that's how the flvs Algebra II lesson looks like? :O
So in the end will Ball 1 be 1.04? I got that from Dividing the old by the new. EX: 2.4/3, 1.9/2.4, 1.5/1.9, 1.2/1.5 then add them together, and divide by 4.
Yeah @tHe_FiZiCx99.
It's easy it's just I tend to come to things that I over look or think way too hard about when it turns out to be incredibly simple; or they explained it badly.
@satellite73 when you're ready.
Um to find the ratio you divide, why did you add and divide by 4?
Well that's what happens when you ask the wrong people for help in school. ^^'
So just divide then times it by the top? Like how satellite73 showed?
I'm familiar with this however they're asking for a common ratio between the 2, i sort of remember how to find it. Not too sure though, I can easily do the 2 and 3rd. I think i might know how to find it :/
Alrighty, getting kind of confused due to the fact that I've been going about it some what wrong. What would Ball 1 end up being?
The ratio for ball I?
Yes.
2.4 / 3 = 0.8 1.9 / 2.4 = 0.79 rounded to 0.8 1.9/1.5 = 0.789 rounded to 0.8 and so on... a_1 = the first term so 3 a_n = a_1 * r^n-1 a_n = 3 * 0.8^n-1
Oh snap I'm getting it. ^_^ Alright, can I call you back to check if I'm doing correctly for Ball II?
sure
common ratio, hm, i don't know how to answer that one :/
1.9/3= 0.63 round = 0.6 1.2/1.9= 0.63 round = 0.6 0.8/1.2= 0.66 round = 0.7 Would this have it's own a_n = a_1 * r^n-1 equation?
Each ball has it own equation.
Cool. 1 minute...
Would it be a_n= 1.9 * 0.6^n-1?
a_1 = the first term
So it will constantly be 3.
a_n = 3 * 0.6^n-1
a_n = 3 * 0.6^n-1 ----------------- a_6 = 3 * 0.6^6-1 a_6 = 3 * 0.6^5 a_6 = 3 * 0.07776 a_6 = 0.23328 Though its asking for the fifth bounce, it says to use height 6... that should technically be: a_5 = 3 * 0.6^5-1 a_5 = 3 * 0.6^4 a_5 = 3 * 0.1296 a_5 = 0.3888
It's adding 1 to it for some reason, the equation is correct --lease I'm pretty sure it is, Find the 3rd height, that would be 0.6^2 = 0.36 * 3 = 1.08 = 1.1... in your table it says 1.2. It does that for everyone of them ._.
Why am I squaring 0.6 by two for the 3rd height?
because its ^n-1 if its for the 5th term it would be from a_N to a_5 r^N-1 --> r^5-1 -> r^4
Alright.
Get it?
So when trying to find the fifth bounce it would be to the fourth power?
yes because its n-1
So why did they say height six when trying to find the fifth bounce? lol They added 1 instead of subtract.
I'm not sure, I'm in algebra I and I've found so many typos in my lesson -- also go to flvs :/ I've actually asked them on here to see lol
lol
Maybe they were referring to using 6 because 6-1 = 5 and they're looking for the successive bounce. Though using 6 would mean find the 6th bounce because of the nth term. That would be a_6
The typos get worse, I've seen many Algebra 2 questions on here from FLVS which couldn't have been answered because of that.
Lol ikr, I should get credit for reporting them, too mcuh work and stuff :/
Yeeaah, I'm going to ignore 6.
Explain why you didn't use 6 so you get credit for trying if anything lol xD
They're trying to refer it as an example. Yeah for real. lol
I got that from the point they used "i.e"
Yeah. Hold up, trying to solve this once and for all. :)
kk
Ball 2's formula should look like this right? a_4 = 3 * 0.6^4-1
yes
Wait it should be a_4 = 3 * 0.6^5-1 Then a_4 = 3 * 0.6^4
Because we're solving for the fifth bounce.
Nope, you're trying to find the 4th bounce right?
For the fifth bounce that would be a_5 = 3 * 0.6^5-1
Fifth lol Doing question 2 Cool just caught myself on that.
It's asking for EACH ball, find the fifth bounce for ball I, II and III
a_4 = 3 * 0.1296 0.1296 round 0.1?
why're you doing a_4?
a_4 = 3 * 0.6^5-1 V 4
Yes, why a_4 though?
Crap a_5 = 3 * 0.6^5-1 V 5
Ugh! a_5 = 3 * 0.6^5-1 V 4
There. o_0 Darn small keyboard.
I'm solving for the fifth bounce, so minus one, left with four.
yes, A_5 = 3 * 0.6^5-1 = a_5 = 3 * 0.6^4
My bad I forgot to change a_4 = to a_5 =
So I'm left with a_5 = 0.3?
3_5 = 0.3
0.4 rounded
Since a is 3
X_X I am completely lost on what you're doing
No I was talking about the first a, "a_5 = 3 * 0.1296" ^
It's all good. I get what you're saying. ^_^
kk find the fifth bounce for all 3 balls
Alright. ^w^
Will take a while so sit back and relax. 'u'
Lol i have to get off soon >.>
It's alright do your thing, you've done your part now it's up to me to do mine. ;) Thank you so much! Goodnight.
I'm doing my own assignment lol, I'll be on my other tab xD I'll be looking back every 15 ish minutes or so :p
K :)
Ball 1: 3_5 = 3 * 0.8^5-1 3 * 0.8^4 3_5 = 3*0.4 3_5 = 1.2
What do I do with 3_5? Feels like I'm suppose to simplify it.
What do I when I get one different? Ball 3: 0.3 0.3 0.3 0.2
3_5 = 3 * 0.3^5-1 3*0.3^4 0.0081 3_5 = 0.02
3_5 ????
a_n = a_1 * r^n-1 3_5 = 3_1 * 0.3^5-1
3, where did it come from?
Ahhh, i get what you did, not you just use a_5
Okay. :)
Ball 1: a_5 = 3 * 0.8^5-1 3 * 0.8^4 a_5 = 3*0.4 a_5 = 1.2 Ball 2: a_5 = 0.4 Ball 3: 0.3 0.3 0.3 0.2 a_5 = 3 * 0.3^5-1 3*0.3^4 0.0081 a_5 = 0.02
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