I just need help setting this problem up: Find the double integral by interpreting it as the volume of a solid.

Question

anonymous · Answer

$$\int\limits_{}^{}\int\limits_{}^{}3-\frac{ 1 }{ 2 }x-\frac{ 3 }{ 4 }y   $$

anonymous · Answer

R= 2x+3y is less than or equal to 12 and both x and y are greater than 0

anonymous · Answer

What I tried doing is this: $$\int\limits_{0}^{6}\int\limits_{0}^{-2/3x+4}f(x,y) dy dx$$

anonymous · Answer

but I got a negative answer

zepdrix · Answer

|dw:1395196701925:dw|Hmmmm seems like you're setting it up correctly.

zepdrix · Answer

And the function is the thing you listed first, yes?

anonymous · Answer

yes, it is.  I guess I'm glad I'm setting it up right :/

anonymous · Answer

as long as I know that, I'll just keep reworking it.  Thank you :)

anonymous · Answer

I may try doing dx first too

zepdrix · Answer

Just make sure your outer integral contains the `constant` boundaries.
Yah doing it in dx might give you some more perspective, just make sure your line is rewritten in terms of y.

anonymous · Answer

definitely.  Thank you.  I was afraid I wasn't understanding the concept.