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prove: 1/ 1-sinx = 1+sinx/cos^2 x
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Start from RHS Replace cos^2 x by 1-sin^2 x
it'll turn to 1+sinx/ 1-sin^2x but I don't know how it'll get to 1/1-sinx because you cant just cross out the sinx
Yeah there you have to apply simply z^2-b^2=(a+b)(a-b) Got the idea? ;)
huh?
I mean a^2-b^2=(a+b)(a-b) 1-sin^2x=.........
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I dont know what youre trying to say...
1+sin x/cos^2 x=(1+sinx)/(1-sin^2 x)=(1+sin x)/(1-sin x)(1+sin x) Can you do it now?
ohhhh...i get it now...thanks...
yw :)
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