Find the standard form of the equation of the parabola with a focus at (0, 2) and a directrix at y = -2
@RadEn
Would you suppose that this parabola is a vertical or a horizontal one? How would you know?
I honestly have no idea..
The focus is a point: (0,2), and the directrix is a straight line: y=-2. Are you able to graph these on coordinate axes, using the Draw feature (below)?
|dw:1395412725985:dw|
Very nice. The vertex of a parabola is always exactly halfway between the focus and the directrix. What point is the vertex of this parabola?
(0, 0)
So, your vertex is at (0,0) and your focus is at (0,2). Does this tell you whether the parabola is horizontal or vertical?
It's vertical
I think..
Wait, is it horizontal?? If so, is the answer y^2=8x?
See http://www.purplemath.com/modules/parabola.htm Your parabola is a vertical one. Yes, p=2, so 4py=8y=x^2, and so y = ??
y=1/8 x^2?
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